Question

Giai pt:

a)\(\sqrt{4x}=\sqrt{5}\)

b)\(\sqrt{4\left(1-x\right)^2}-6=0\)

c)\(\sqrt{x^2-4x+4}=3\)

Answer 1

\(\sqrt{4x}=\sqrt{5}\Rightarrow4x=5\Leftrightarrow x=1,25\)

\(\sqrt{4\left(1-x\right)^2}-6=0\Leftrightarrow4\left(1-x\right)^2=36\Leftrightarrow\left(1-x\right)^2=9\Leftrightarrow\left[{}\begin{matrix}1-x=3\\1-x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)

\(\sqrt{x^2-4x+4}=\sqrt{\left(x-2\right)^2}=\left|x-2\right|=3\Leftrightarrow\left[{}\begin{matrix}x-2=-3\\x-2=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=5\end{matrix}\right.\)