\(x^4+x^2-12=0\)
\(\Leftrightarrow x^4+2\cdot x^2\cdot\frac{1}{2}+\frac{1}{4}-\frac{49}{4}=0\)
\(\Leftrightarrow\left(x^2+\frac{1}{2}\right)^2=\frac{49}{4}=\left(\frac{7}{2}\right)^2\)( vì \(x^2+\frac{1}{2}>0\forall x\))
\(\Leftrightarrow x^2+\frac{1}{2}=\frac{7}{2}\)
\(\Leftrightarrow x^2=3\)
\(\Leftrightarrow x=\pm\sqrt{3}\)
Vậy....