a)đk : x\(\ge2\)\(< =>\sqrt{x-2+2\sqrt{x-2}+1}+\sqrt{x-2+2.3\sqrt{x-2}+9}=2\)<=> \(\sqrt{\left(\sqrt{x-2}-1\right)^2}+\sqrt{\left(\sqrt{x-2}+3\right)^2}=2\)
<=> \(\sqrt{x-2}-1+\sqrt{x-2}+3=2\)
<=> \(2\sqrt{x-2}=0\)
<=> \(\sqrt{x-2}=0\)
<=> x-2=0
<=> x=2 (tmđkxđ)
vậy ..........
mk đăng câu A trc, câu kia đang nghĩ nha
tick