ĐKXĐ: \(x\ge\frac{1}{2}\)
PT\(\Leftrightarrow\sqrt{2x-1}-1-x^3+1+2x^2-2x=0\)
\(\Leftrightarrow\frac{2\left(x-1\right)}{\sqrt{2x-1}+1}-\left(x-1\right)\left(x^2+x+1\right)+2x\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(\frac{2}{\sqrt{2x-1}+1}-x^2-x-1+2x\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(\frac{2}{\sqrt{2x-1}+1}-x^2+x-1\right)=0\)
\(\Leftrightarrow x-1=0\)(ngoặc đằng sau dùng đkxđ để chứng minh>0)
\(\Leftrightarrow x=1\)(thỏa mãn)