pt<=>x2(x2-2x+2)+5x(x2-2x+2)+2(x2-2x+2)=0
<=>\(\left[{}\begin{matrix}x^2+5x+2=0\left(1\right)\\x^2-2x+2=0\left(vn\right)\end{matrix}\right.\)
\(\left(1\right)\Leftrightarrow\left[{}\begin{matrix}x=\frac{-5+\sqrt{17}}{2}\\x=\frac{-5-\sqrt{17}}{2}\end{matrix}\right.\)