Question

Giải phương trình sau:

(x - 1)(x + 5)/3 - (x +2)(x+5)/12 = (x -1)(x+2)/2

Answer 1

\(\frac{\left(x-1\right)\left(x-5\right)}{3}-\frac{\left(x+2\right)\left(x+5\right)}{12}=\frac{\left(x-1\right)\left(x+2\right)}{2}\)

\(\Leftrightarrow\frac{4\left(x^2-6x+5\right)}{12}-\frac{\left(x+2\right)\left(x+5\right)}{12}=\frac{6\left(x^2+x-2\right)}{12}\)

\(\frac{4x^2-24x+20-\left(x^2+7x+10\right)-6x^2-6x+12}{12}=0\)

\(\Leftrightarrow4x^2-24x+20-x^2-7x-10-6x^2-6x+12=0\)

\(\Leftrightarrow-3x^2-37x+22=0\)

Pt nghiệm vô tỉ