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\(\Leftrightarrow2\left(x^2+2x-3\right)-3\sqrt{x^2+2x-3}+1=0\)
Đặt \(\sqrt{x^2+2x-3}=a\ge0\)
\(\Leftrightarrow2a^2-3a+1=0\Rightarrow\left[{}\begin{matrix}a=1\\a=\frac{1}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\sqrt{x^2+2x-3}=1\\\sqrt{x^2+2x-3}=\frac{1}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+2x-3=1\\4\left(x^2+2x-3\right)=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+2x-4=0\\4x^2+8x-13=0\end{matrix}\right.\) (casio)