a) \(3x+\sqrt{2}=2\left(x+\sqrt{2}\right)\)
\(\Leftrightarrow3x+\sqrt{2}=2x+2\sqrt{2}\)
\(\Leftrightarrow x=\sqrt{2}\)
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b) ĐKXĐ: \(x\ge2\)
\(3\sqrt{x-2}-\sqrt{x^2-4}=0\)
\(\Leftrightarrow3\sqrt{x-2}-\sqrt{x-2}\cdot\sqrt{x+2}=0\)
\(\Leftrightarrow\sqrt{x-2}\cdot\left(3-\sqrt{x+2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x-2}=0\\\sqrt{x+2}=3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=7\end{matrix}\right.\) ( thỏa )
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