ta có : \(5\left(\sqrt{x}-2\right)+4\sqrt{x}=8-3\sqrt{x}\)
\(\Leftrightarrow5\sqrt{x}-10+4\sqrt{x}-8+3\sqrt{x}=0\Leftrightarrow12\sqrt{x}-18=0\)
\(\Leftrightarrow\sqrt{x}=\dfrac{18}{12}=\dfrac{3}{2}\Leftrightarrow x=\dfrac{9}{4}\) vậy \(x=\dfrac{9}{4}\)
\(5\left(\sqrt{x}-2\right)+4\sqrt{x}=8-3\sqrt{x}\)
\(\Leftrightarrow5\sqrt{x}-10+4\sqrt{x}=8-3\sqrt{x}\)
\(\Leftrightarrow5\sqrt{x}+4\sqrt{x}+3\sqrt{x}=10+8\)
\(\Leftrightarrow18\sqrt{x}=18\)
\(\Leftrightarrow\sqrt{x}=1\)
\(\Leftrightarrow x=1\)