ĐK: \(x\ne0\)
\(\frac{\left(x+2\right)\left(x^2-2x+4\right)-\left(x-2\right)\left(x^2+2x+4\right)}{\left(x^2+2x+4\right)\left(x^2-2x+4\right)}=\frac{6}{x\left(x^4+4x^2+16\right)}\)
\(\Leftrightarrow\frac{\left(x^3+8\right)-\left(x^3-8\right)}{x^4+4x^2+16}=\frac{6}{x\left(x^4+4x^2+16\right)}\)
\(\Leftrightarrow16=\frac{6}{x}\)
\(\Rightarrow x=\frac{3}{8}\)
giải phương trình sau :
a) 5-(x-6) = 4(3-2x) b) 2x(x+2)2-8x2 = 2(x-2)(x2+4)
c) 7-(2x+4) = -(x+4) d) (x+1)(2x-3) = (2x-1)(x+5
f) \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
e) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
Giải các bất phương trình sau :
a) \(15-2x\left(1-x\right)< 2x^2-4x+5\)
b) \(x^2-\frac{x\left(3x+2\right)}{3}< \frac{x-6}{3}\)
c) \(1+\frac{x+4}{3}< x-\frac{x-3}{2}\)
d) \(\left(\frac{2x+1}{2}\right)^2+\frac{3x\left(1-x\right)}{3}-\frac{5x}{4}\le1\)
Giải các phương trình:
\(a,\frac{2x+1}{x^2-5x+4}+\frac{5}{x-1}=\frac{2}{x-4}\)
\(b,\frac{7}{8x}-\frac{x-5}{4x^2-8x}=\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
bài 1 giải phương trình
\(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x^2-4}\)
\(\frac{3}{5x-1}+\frac{3}{3-5x}=\frac{4}{\left(1-5x\right)\left(5x-3\right)}\)
\(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)
\(\frac{5-x}{4x^2-8x}+\frac{7}{8x}=\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
Giải các phương trình
a) \(\frac{15x}{x^2+3x-4}=\frac{12}{x+4}+\frac{4}{x-1}+1\)
b) \(x\left(x-2\right)\left(x-1\right)\left(x+1\right)=24\)
c) \(\frac{x^2-2x+2}{x-1}+\frac{x^2-8x+20}{x-4}=\frac{x^2-4x+6}{x-2}+\frac{x^2-6x+12}{x-3}\)
Bài 1: Giải phương trình sau:
a) \(\left|\frac{3x-6}{1-2x}\right|=x-2\)
b) \(\left|-2x+8\right|=\frac{x^2-6x+8}{x+3}\)
c) \(\frac{\left|x\right|-6}{x^2-36}=2\)
d) \(\frac{\left|x^2-4x+3\right|}{5x^2-7x+2}=x-3\)
e) \(\frac{-2x^2+7x-4}{\left|2x+1\right|}=4-x\)
f) \(\frac{\left|x^2+5x+4\right|}{x^2+3x+2}=x+4\)
\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{\left(x-4\right)}{x\left(x+2\right)}=0\)
\(\frac{1}{x-2}\frac{6}{x+3}=\frac{5}{6-x^2-x}\)
\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{2\left(x+2\right)^2}{x^6-1}\)
Giải phương trình:
a) \(\frac{4x-8+\left(4-2x\right)}{x^2+1}=0\)
b) \(\frac{x^2\left(x-3\right)}{x}=0\)
c) \(\frac{\left(x+2\right)\left(2x-1\right)-x-2}{x^2-x+1}=0\)
Cho A=\(\left(\frac{x+2}{x^2-2x}+\frac{x-6}{x^2-4}-\frac{x-2}{x^2+2x}\right):\frac{2x-7}{x^2-4x+4}\left(x\ne0,2,-2,\frac{7}{2}\right)\)
a)Rút gon A
b)Tìm x để A nguyên
