Question

\(\frac{1+y}{9}=\frac{1+2y}{7}=\frac{1+3y}{x}\) Tìm x 

Answer 1

\(\frac{1+y}{9}=\frac{1+2y}{7}\)

\(\Rightarrow\left(1+y\right)7=\left(1+2y\right)9\)

\(\Rightarrow7+7y=9+18y\)

\(\Rightarrow7-9=18y-7y\)

\(\Rightarrow-2=11y\)

\(\Rightarrow y=\frac{-2}{11}\)

Thay \(y=\frac{-2}{11}\)

\(\frac{1+\frac{-2}{11}}{9}=\frac{1+3.\frac{-2}{11}}{x}\)

\(\Rightarrow\frac{\frac{9}{11}}{9}=\frac{\frac{5}{11}}{x}\)

\(\Rightarrow\frac{9}{11}.x=\frac{5}{11}.9\)

\(\Rightarrow\frac{9x}{11}=\frac{45}{11}\)

\(\Rightarrow9x=45\)

\(\Rightarrow x=5\)