Question

Đơn giản biểu thức:

\(A=\left(a-b+c\right)-\left(b-c-d\right)+\left(c-d+a\right)\)

\(B=\left(a+b-c\right)+\left(b+c-a\right)-\left(a-c\right)\)

\(C=-\left(4a+5b-c\right)-\left(5b+3c\right)\)

\(D=\left(a-3b+c\right)-\left(2a-b+c\right)\)

Answer 1

A=(a-b+c)-(b-c-d)+(c-d+a)

A=a-b+c-b+c+d+c-d+a

A=2a-2b-3c

B=( a + b - c ) + ( b + c - a ) - ( a - c )

B=a + b - c + b + c - a - a + c

B=2b + c - a

Answer 2

C = - ( 4a + 5b + c) - ( 5b + 3c )

C = -4a - 5b - c - 5b -3c

C= -4a - 10b - 4c

D= ( a - 3b + c) - ( 2a -b +c)

D= a - 3b +c - 2a + b -c

D= a - 2b