\(\frac{b+c-a}{a}=\frac{a+c-b}{b}=\frac{a+b-c}{c}=\frac{a+b+c}{a+b+c}=1\)
\(\Rightarrow\left\{{}\begin{matrix}\frac{b+c-a}{a}=1\\\frac{a+c-b}{b}=1\\\frac{a+b-c}{c}=1\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}b+c=2a\\a+c=2b\\a+b=2c\end{matrix}\right.\)
\(\Rightarrow Q=\frac{\left(a+b\right)}{b}.\frac{\left(b+c\right)}{c}.\frac{\left(a+c\right)}{c}=\frac{2c.2a.2b}{abc}=8\)