❏Ta có : \(\left\{{}\begin{matrix}\dfrac{x}{2}=\dfrac{y}{2}\\xy=54\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=y\\xy=54\end{matrix}\right.\)
\(\Rightarrow x^2=54\Rightarrow x=y=\sqrt{54}=3\sqrt{6}\)
Ta có : \(\left\{{}\begin{matrix}\frac{x}{2}=\frac{y}{2}\\xy=54\end{matrix}\right.=>\left\{{}\begin{matrix}x=y\\xy=54\end{matrix}\right.\)
⇒\(x^2=54\)=>x=y=\(\sqrt{54=3\sqrt{6}}\)
Sửa đề: x/3=y/2
Đặt x/3=y/2=k
=>x=3k; y=2k
Ta có: xy=54
=>6k2=54
=>k2=9
TH1: k=3
=>x=9; y=6
TH2: k=-3
=>x=-9; y=-6
