Question

\(\dfrac{x+1}{x+2}=\dfrac{0,8}{1,2}\)

Answer 1

tích trung tỉ bằng tihs ngoại tỉ là ra ý mà

Answer 2

\(\dfrac{x+1}{x+2}=\dfrac{0,8}{1,2}\) \(\Leftrightarrow0,8\left(x+2\right)=1,2\left(x+1\right)\)

\(\Leftrightarrow0,8x+1,6=1,2x+1,2\) \(\Leftrightarrow0,4x=0,4\Leftrightarrow x=1\)

vậy \(x=1\)

Answer 3

\(\dfrac{x+1}{x+2}=\dfrac{0,8}{1,2}\)

\(\Rightarrow\left(x+1\right)1,2=\left(x+2\right)0,8\)

\(1,2x+1,2=0,8x+1,6\)

\(1,2x-0,8x=1,6-1,2\)

\(0,4x=0,4\)

\(x=1\)