Question

\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)

Answer 1

\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)

\(\Leftrightarrow\dfrac{11\left(x-3\right)}{55}=\dfrac{-5\left(5-2x\right)}{55}\)

\(\Leftrightarrow11x-33=-25+10x\)

\(\Leftrightarrow11x-10x=-25+33\)

\(\Leftrightarrow x=8\)

Answer 2

\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\\ \dfrac{\left(x-3\right).-11}{-55}=\dfrac{\left(5-2x\right).5}{-55}\\ \dfrac{-11x-33}{-55}=\dfrac{25-10x}{-55}\\ -11x-33=25-10x\\ -11x+10x=25-33\\ -x=-8\\ x=8 \)