x−3/x−5=5+x/x−11 (1)
ĐKXĐ: x-5≠0 và x-11≠0
(1)<=>(x-3)(x-11)/(x-5)(x-11)=(x-5)(5+x)/(x-11)(x-5)
<=>x^2-11x-3x+33=5x+x^2-25-5x
<=>x^2-11x-3x-5x-x^2+5x=-25-33
<=>-14x=-58
<=>x=29/7
x−3/x−5=5+x/x−11 (1)
ĐKXĐ: x-5≠0 và x-11≠0
(1)<=>(x-3)(x-11)/(x-5)(x-11)=(x-5)(5+x)/(x-11)(x-5)
<=>x^2-11x-3x+33=5x+x^2-25-5x
<=>x^2-11x-3x-5x-x^2+5x=-25-33
<=>-14x=-58
<=>x=29/7
Tìm x, biết:
\(x=\dfrac{19}{11}\cdot\dfrac{5}{14}+\dfrac{1}{11}\cdot\dfrac{5}{7}-\sqrt{\dfrac{25}{4}}\cdot\dfrac{2}{11}\)
Tìm x biết :
a, \(\left|x-\dfrac{5}{3}\right|< \dfrac{1}{3}\)
b, \(\left|x+\dfrac{11}{2}\right|>\left|-5,5\right|\)
c, \(\dfrac{2}{5}< \left|x-\dfrac{7}{5}\right|< \dfrac{3}{5}\)
\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)
giúp mình với
gấp gấp lắm
1/ tìm x
a) \(x.\left(x+\dfrac{2}{3}\right)=0\)
2/tìm giá trị nhỏ nhất của các biểu thức
a) \(\left|x+\dfrac{4}{6}\right|\)
b) \(\left|x-\dfrac{1}{3}\right|\)
3/ tính
a) \(\left(1+2+3+...90\right).\left(12.34-668\right):\left(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{6}\right)\)
b) \(\dfrac{\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}+\dfrac{\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}}{\dfrac{5}{4}-\dfrac{5}{6}+\dfrac{5}{8}}\)
I. Tìm x
a. \(\left|x\right|=1,21\)
b. \(\dfrac{11}{12}-\left(\dfrac{2}{5}-x\right)=\dfrac{2}{3}\)
c. \(\dfrac{3}{4}+\dfrac{1}{4}\div x=\dfrac{2}{5}\)
d. \(3^x=81\)
e. \(\dfrac{1}{2}\times\left|x\right|-\dfrac{5}{2}=\dfrac{8}{3}\)
f. \(2^{x-3}=4\)
\(B=x+\dfrac{0,2-0,375+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}với\) x=\(-\dfrac{1}{3}\)
6)a) \(\left|\dfrac{5}{3}:x\right|=\left|-\dfrac{1}{6}\right|\)
b)\(\left|\dfrac{3}{4}x-\dfrac{3}{4}\right|-\dfrac{3}{4}=\left|-\dfrac{3}{4}\right|\)
1. tìm x
a.\(\dfrac{1}{5}+x=\dfrac{13}{30}\)
b.\(\dfrac{1}{6}-x=\dfrac{5}{12}\)
c. \(x.\left(\dfrac{-1^{ }}{2}\right)^2=\dfrac{1}{16}\)
d. \(x:\dfrac{7}{11}=\dfrac{9}{33}\)
e. \(\dfrac{3}{5}.x=\dfrac{-21}{10}\)
x+\(\dfrac{0,2-0.3+5+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}\)voi x =\(\dfrac{1}{3}\)
giup mk voi can gap
Tìm x
a) \(\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\left|\left(-3,2\right)+\dfrac{2}{5}\right|\)
b) \(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)