Question

\(\dfrac{3}{x-1}+2y=5\)

\(\dfrac{1}{x-1}-y-\dfrac{15}{2}\)

Answer 1

$\begin{cases}\dfrac{3}{x-1}+2y=5\\\dfrac{1}{x-1}-y=\dfrac{15}{2}\\\end{cases}$

`<=>` $\begin{cases}\dfrac{3}{x-1}+2y=5\\\dfrac{2}{x-1}-2y=15\\\end{cases}$

`<=>` $\begin{cases}\dfrac{3}{x-1}+2y=5\\\dfrac{5}{x-1}=20\\\end{cases}$

`<=>` $\begin{cases}\dfrac{3}{x-1}+2y=5\\\dfrac{1}{x-1}=4\\\end{cases}$

`<=>` $\begin{cases}12+2y=5\\x-1=\dfrac{1}{4}\\\end{cases}$

`<=>` $\begin{cases}2y=-7\\x=\dfrac{5}{4}\\\end{cases}$

`<=>` $\begin{cases}y=\dfrac{-7}{2}\\x=\dfrac{5}{4}\\\end{cases}$

Vậy HPT có nghiệm `(x,y)=(5/4,-7/2)`