Question

\(-\dfrac{2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x-1\right)\)

Answer 1

\(-\dfrac{2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x-1\right)\)

\(\Rightarrow-\dfrac{2}{3}x+\dfrac{1}{6}=\dfrac{2}{3}x-\dfrac{1}{3}\)

\(\Rightarrow-\dfrac{2}{3}x-\dfrac{2}{3}x=-\dfrac{1}{3}-\dfrac{1}{6}\)

\(\Rightarrow-\dfrac{4}{3}x=-\dfrac{1}{2}\Rightarrow x=\dfrac{3}{8}\)

Chúc bạn học tốt!!!

Answer 2

\(=>-\dfrac{2}{3}x+-\dfrac{2}{3}.-\dfrac{1}{4}=\dfrac{1}{3}.2x-\dfrac{1}{3}\)

\(=>-\dfrac{2x}{3}+\dfrac{1}{6}=\dfrac{2x}{3}-\dfrac{1}{3}\)

\(=>-\dfrac{2x}{3}-\dfrac{2x}{3}=-\dfrac{1}{3}-\dfrac{1}{6}\)

\(=>-\dfrac{4x}{3}=-\dfrac{1}{2}\)

\(=>-4x=-\dfrac{1}{2}.3=-\dfrac{3}{2}\)

\(=>x=-\dfrac{3}{2}:-4=\dfrac{3}{8}\)

CHÚC BẠN HỌC TỐT..........

Answer 3

khó quá bạn ơi !