ĐKXĐ \(x\ne\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{1}{2x-1}+\dfrac{2x\left(2x-1\right)}{2x-1}=0\)
\(\Rightarrow1+2x\left(2x-1\right)=0\)
\(\Leftrightarrow4x^2-2x+1=0\)
\(\Leftrightarrow\left(2x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}=0\)
Do \(\left(2x-\dfrac{1}{2}\right)^2\ge0\Rightarrow\left(2x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}>0;\forall x\)
Pt đã cho vô nghiệm