Question

(\(\dfrac{1}{12}\) + x ) - \(\dfrac{-1}{2}\) = \(\dfrac{-2}{3}\)                                                               

Answer 1

`(1/12 + x ) - (-1)/2 =(-2)/3`

`(1/12 + x )  +1/2 =(-2)/3`

`1/12 + x= -2/3 -1/2`

`1/12 + x=-4/6 - 3/6`

`1/12 + x=-7/6`

` x=-7/6 -1/12`

`x=-5/4`

Answer 2

\(\left(\dfrac{1}{12}+x\right)-\dfrac{-1}{2}=\dfrac{-2}{3}\)

\(\dfrac{1}{12}+x=\dfrac{-2}{3}+\dfrac{-1}{2}=\dfrac{-4}{6}+\dfrac{-3}{6}\)

\(\dfrac{1}{12}+x=\dfrac{7}{6}\)

\(x=-\dfrac{7}{6}-\dfrac{1}{12}=-\dfrac{14}{6}-\dfrac{1}{12}\)

\(x=-\dfrac{15}{12}\)

Answer 3

\(\left(\dfrac{1}{12}+x\right)-\dfrac{-1}{2}=\dfrac{-2}{3}\\ \left(\dfrac{1}{12}+x\right)+\dfrac{1}{2}=\dfrac{-2}{3}\\\dfrac{1}{12}+x=\dfrac{-2}{3}-\dfrac{1}{2}\\ \dfrac{1}{12}+x=\dfrac{-7}{6}\\ x=\dfrac{-7}{6}-\dfrac{1}{12}\\ x=\dfrac{-5}{4}\)