\(\dfrac{-2}{3}x+\dfrac{-3}{7}+\dfrac{1}{2}x=\dfrac{-5}{6}\)
\(\Rightarrow\dfrac{-2}{3}x+\dfrac{1}{2}x=\dfrac{-5}{6}-\left(\dfrac{-3}{7}\right)\)
\(\Rightarrow\dfrac{-1}{6}x=\dfrac{-17}{42}\)
\(\Rightarrow x=\dfrac{-17}{42}:\left(\dfrac{-1}{6}\right)\)
\(\Rightarrow x=\dfrac{17}{7}\)
Vậy...
\(\dfrac{-2}{3}x+\dfrac{-3}{7}+\dfrac{1}{2}x=\dfrac{5}{6}\)
\(\dfrac{-2}{3}x+\dfrac{1}{2}x=\dfrac{-5}{6}-\dfrac{-3}{7}\)
\(\dfrac{-2}{3}x+\dfrac{1}{2}x=\dfrac{-17}{42}\)
\(\left(\dfrac{-2}{3}+\dfrac{1}{2}\right)x=\dfrac{-17}{42}\)
\(\dfrac{-1}{6}x=\dfrac{-17}{42}\)
\(x=\dfrac{-17}{42}:\dfrac{1}{6}\)
\(x=\dfrac{-17}{7}\)
Vậy .....
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