Ta có :
\(\dfrac{3}{3\sqrt{3}-1}=\dfrac{3\left(3\sqrt{3}+1\right)}{\left(3\sqrt{3}-1\right)\left(3\sqrt{3}+1\right)}=\dfrac{3+9\sqrt{3}}{27-1}=\dfrac{3+9\sqrt{3}}{26}\)
\(=>\dfrac{3}{26}+\dfrac{9\sqrt{3}}{26}>\dfrac{1}{3}\)
Đề sai phải là \(=>\dfrac{3}{26}+\dfrac{9\sqrt{3}}{26}>\dfrac{1}{3}\)
CMR: \(\sqrt[3]{\sqrt[3]{2}-1}=\sqrt[3]{\dfrac{1}{9}}-\sqrt[3]{\dfrac{2}{9}}+\sqrt[3]{\dfrac{4}{9}}\)
CMR: \(A=\sqrt{\dfrac{1}{1^2}+\dfrac{1}{2^2}+\dfrac{1}{3^2}}+\sqrt{\dfrac{1}{1^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}}+\sqrt{\dfrac{1}{1^2}+\dfrac{1}{2016^2}+\dfrac{1}{2017^2}}+\sqrt{\dfrac{1}{1^2}+\dfrac{1}{2017^2}+\dfrac{1}{2018^2}}\)là 1 số hữu tỉ
CMR:\(\dfrac{1}{1+\sqrt{3}}+\dfrac{1}{\sqrt{5}+\sqrt{7}}+\dfrac{1}{\sqrt{9}+\sqrt{11}}+...+\dfrac{1}{\sqrt{97}+\sqrt{99}}>\dfrac{9}{4}\)
Cho am3 = bn3 = cp3 và \(\dfrac{1}{m}+\dfrac{1}{n}+\dfrac{1}{p}=1\)
CMR: \(\sqrt[3]{a}+\sqrt[3]{b}+\sqrt[3]{c}=\sqrt[3]{am^2+bn^2+cp^2}\)
Cho \(x=\dfrac{3}{\sqrt[3]{4}-\sqrt[3]{2}+1}y=\dfrac{6}{4+\sqrt[3]{4}+\sqrt[3]{16}}\)
CMR x+y là 1 số tự nhiên
Bài 1: cho a, b > 0 và a + b <= 1. CMR: \(\dfrac{1}{3a^2+b^2}+\dfrac{2}{b^2+3ab}>=3\)
Bài 2: cho x, y, z >=0 thỏa mãn x + y + z >0. CMR: \(\dfrac{x}{4x+4y+z}+\dfrac{y}{4y+4z+x}+\dfrac{z}{4z+4x+y}< =\dfrac{1}{3}\)
Bài 3: cho x, y, z > 0 thỏa mãn \(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=3\)
Tìm GTNN của \(\dfrac{1}{\sqrt{2x^2+y^2+3}}+\dfrac{1}{\sqrt{2y^2+z^2+3}}+\dfrac{1}{\sqrt{2z^2}+x^2+3}\)
CMR: \(\dfrac{3x+3}{x\sqrt{x}-1}\) < \(\dfrac{1}{3}\)
CMR : \(\dfrac{\sqrt{x}-1}{x+\sqrt{x}+1}\)<\(\dfrac{1}{3}\)
Thực hiến phép tính :
a, \(\dfrac{1}{3+\sqrt{2}}+\dfrac{1}{3-\sqrt{2}}\)
b, \(\dfrac{2}{3\sqrt{2}-4}-\dfrac{2}{3\sqrt{2}+4}\)
c, \(\dfrac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}+\dfrac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}\)
d, \(\dfrac{3}{2\sqrt{2}-3\sqrt{3}}-\dfrac{3}{2\sqrt{2}+3\sqrt{3}}\)
e, \(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}\)
g, \(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-6\sqrt{20}}}}\)
