1) Xét:
\(\left(a-b\right)+\left(c-d\right)=a-b+c-d\)
\(\left(a+c\right)-\left(b+d\right)=a+c-b-d=a-b+c-d\) (giao hoán)
\(\Rightarrow\left(a-b\right)+\left(c-d\right)=\left(a+c\right)-\left(b+d\right)\)
2) Xét:
\(-\left(-a+c-d\right)-\left(-c-a+d\right)=a-c+d+c+a-d\)
\(=\left(a-a\right)+\left(c-c\right)+\left(d-d\right)\)
\(=0\)
Vậy \(-\left(-a+c-d\right)-\left(-c-a+d\right)=0\)
3) Xét:
\(a\left(b-c-d\right)-a\left(b+c-d\right)\)
\(=ab-ac-ad-ab-ac+ad\)
\(=\left(ab-ab\right)+\left(ac-ac\right)+\left(-ad+ad\right)\)
\(=0\)
Vậy \(a\left(b-c-d\right)-a\left(b+c-d\right)=0\)
P/s: test lại đề phần 2) dấu của số trừ