\(3x+y+6z\le5xyz+5xz^2+x^2y+x^2z=x\left(y+z\right)\left(5z+x\right)\)
\(\Rightarrow3x+y+6z\le\frac{1}{2}.2x\left(y+z\right)\left(5z+x\right)\le\frac{1}{54}\left(3x+y+6z\right)^3\)
\(\Rightarrow\left(3x+y+6z\right)^2\ge54\)
\(\Rightarrow3x+y+6z\ge3\sqrt{6}\)
\(\Rightarrow P\ge6\sqrt{6}\)