\(x-y=7\Rightarrow x=7+y\)
B=\(\dfrac{3x-7}{2x+y}-\dfrac{3y+7}{2x+y}\)
=\(\dfrac{3\left(7+y\right)-7}{2\left(7+y\right)+y}-\dfrac{3y+7}{2y+7+y}\)
=\(\dfrac{21+3y-7}{14+2y+y}-\dfrac{3y+7}{3y+7}\)
=\(\dfrac{14+3y}{14+3y}-\dfrac{3y+7}{3y+7}\)
=1-1=2
Vậy B=2