(a+2c)(b+d)=(a+c)(b+2d)
<=> ab + ad + 2bc + 2cd = ab + 2ad + bc + 2cd
<=> bc - ad = 0. (1)
Mà a/b=c/d <=> ad=bc => (1) luôn đúng. => đpcm
Từ ( a + 2c ) ( b + d ) = ( a + c ) ( b + 2d )
\(\Rightarrow\frac{a+2c}{b+2d}=\frac{a+c}{b+d}\)
Đặt \(\frac{a}{b}=\frac{c}{d}=k\)
Suy ra \(\begin{cases}a=bk\\c=dk\end{cases}\)\(\Rightarrow\frac{a+2c}{b+2d}=\frac{a+c}{b+d}\)\(\Leftrightarrow\frac{bk+2dk}{b+2d}=\frac{bk+dk}{b+d}\)
Xét VT \(\frac{bk+2dk}{b+2d}=\frac{k\left(b+2d\right)}{b+2d}=k\left(1\right)\)
Xét VP \(\frac{bk+dk}{b+d}=\frac{k\left(b+d\right)}{b+d}=k\left(2\right)\)
Từ (1) và (2) -->Đpcm