Lời giải:
Ta có: \(3=\tan a=\frac{\sin a}{\cos a}\Rightarrow \sin a=3\cos a\)
Khi đó:
\(\frac{\sin ^3a-\cos ^3a}{\sin ^3a+\cos ^3a}=\frac{(3\cos a)^3-\cos ^3a}{(3\cos a)^3+\cos ^3a}=\frac{\cos ^3a(3^3-1)}{\cos ^3a(3^3+1)}=\frac{3^3-1}{3^3+1}=\frac{13}{14}\)
Ta có đpcm.