a: \(cosA=\dfrac{AB^2+AC^2-BC^2}{2\cdot AB\cdot AC}=\dfrac{11}{39}\)
=>góc A=74 độ
\(cosB=\dfrac{12^2+15^2-13^2}{2\cdot12\cdot15}=\dfrac{5}{9}\)
=>góc B=56 độ
=>góc C=50 độ
b: \(S_{ABC}=\dfrac{1}{2}\cdot15\cdot13\cdot sin50\simeq74,69\left(cm^2\right)\)
AB/sinC=2R
=>2R=12/sin50
=>R=7,83(cm)