a) ΔABC có:
\(\widehat{BAC}+\widehat{ABC}+\widehat{ACB}=180^0\)
\(\Rightarrow\widehat{ABC}+\widehat{ACB}=180^0-\widehat{BAC}\)
Mà: \(\widehat{ABC}=\widehat{ACB}\left(GT\right)\)
\(\Rightarrow\widehat{ABC}=\widehat{ACB}=\frac{180^0-\widehat{BAC}}{2}=\frac{180^0-108^0}{2}=36^0\)
b/ Thiếu đề