tìm x biết :
a) \(\left|x+\dfrac{1}{2}\right|\)=\(\dfrac{5}{2}\) b) \(\left|2x-\dfrac{2}{3}\right|\)+\(\dfrac{1}{3}\)=0 c) |x-2| = 2x + 1
làm đầy đủ theo các bước nhé
Tìm x biết :
a) \(^{\dfrac{4}{9}+x=\dfrac{5}{3}}\)
b)\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
c) \(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
d)\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
Tìm x:
3.(3x+\(\dfrac{1}{2}\))\(^3\)+\(\dfrac{1}{9}\)=0
60%x+\(\dfrac{2}{3}\)x=\(\dfrac{1}{3}\).6\(\dfrac{1}{3}\)
Bài 1: Tìm x, biết
a) 3\(\dfrac{1}{3}\) x+ 16\(\dfrac{3}{4}\) = -13,25
b) 3\(\dfrac{2}{7}\).x - \(\dfrac{1}{8}\) = 2\(\dfrac{3}{4}\)
c) x : 4\(\dfrac{1}{3}\) = - 2,5
d) (\(\dfrac{3x}{7}\) + 1) : (-4) = \(\dfrac{-1}{28}\)
giúp em
3. tìm x
a. x+ \(\dfrac{1}{3}\)=\(\dfrac{1}{2}\)
b. \(\dfrac{5}{3}\) - x =\(\dfrac{4}{7}\)
c. \(\dfrac{4}{7}\). x -\(\dfrac{2}{3}\)=\(\dfrac{1}{5}\)
d.\(\dfrac{2}{5}\): x =-\(\dfrac{1}{4}\)
\(\color{red}{\text{Tìm X }}\):
\(a) |x|=\)\(\dfrac{1}{5}\)\(+\)\(\dfrac{3}{4}\)
\(b)|x-5|=-\)\(\dfrac{5}{3}+\dfrac{1}{4}\)
\(\color{red}{\text{Giúp em với ak}}\)
Bài 1: Rút gọn các phân số sau: a/ \(\dfrac{-63}{81}\), b/ \(\dfrac{5.6}{9.35}\), c/ \(\dfrac{7.2+8}{2.14.5}\)
Bài 2: Tìm X: a/ \(\dfrac{4}{7}\)-X = \(\dfrac{1}{2}\). X + \(\dfrac{2}{7}\); b/ X : \(3\dfrac{1}{5}\)= \(1\dfrac{1}{2}\); c/ X . \(\dfrac{3}{4}\)= \(-1\dfrac{5}{8}\)
Bài 3: Tính giá trị biểu thức: A= \(\dfrac{-3}{5}\)+ ( \(\dfrac{-2}{5}\)+ 2 ); B= \(\dfrac{3}{7}\)+ ( -\(\dfrac{1}{5}\) + \(\dfrac{-3}{7}\) ); C= ( -\(\dfrac{5}{24}\) + 0,75 + \(\dfrac{7}{12}\) ) : (-2. \(\dfrac{1}{8}\))
Bài 4: Tìm X: a/ ( \(2\dfrac{1}{3}\) + \(3\dfrac{1}{2}\) ) . X = \(-4\dfrac{1}{6}\) + \(3\dfrac{1}{7}\); b/ X : ( \(3\dfrac{1}{2}\) - \(5\dfrac{1}{6}\) ) = \(4\dfrac{1}{5}\) - \(6\dfrac{2}{3}\)
Các bạn giúp mình nha!
1) tính hợp lí ( nếu có thể )
c) \(\dfrac{2}{-11}\). 6\(\dfrac{2}{7}\)+ \(\dfrac{3}{7}\):3 + 5 d) 1,75 : 5 + 2,5 . ( \(4^2\)- 4. 4,1)
2) tìm x
a) 1/2-x=-1/6 b) x+3,5=7,8-12,6:2 c) 7/35 = 35-x/-105
Tìm số nguyên \(x\), biết rằng :
\(4\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)