\(P=\frac{4\left(x-9\right)+36}{\sqrt{x}-3}=\frac{4\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)+36}{\sqrt{x}-3}\)
\(P=4\left(\sqrt{x}+3\right)+\frac{36}{\sqrt{x}-3}=4\left(\sqrt{x}-3\right)+\frac{36}{\sqrt{x}-3}+12\)
\(\Rightarrow P\ge2\sqrt{\frac{4\left(\sqrt{x}-3\right).36}{\sqrt{x}-3}}+12=36\)
\(P_{min}=36\) khi \(\left(\sqrt{x}-3\right)^2=9\Rightarrow x=36\)