a. Xét △MNK và △MPN có:
\(\widehat{M}\) chung
\(\widehat{MNK}=\widehat{MPN}\) ( gt)
\(\rightarrow\)△MNK ∼ △MPN ( g.g)
b. Có △MNK ∼ △MPN ( theo câu a), ta có:
\(\frac{MN}{MP}=\frac{MK}{MN}\)= \(\frac{NK}{NP}\)hay \(\frac{4}{6}\)= \(\frac{MK}{4}\)
\(\rightarrow\)\(MK=\frac{4.4}{6}\) = 2,67 cm