a ) Theo định lý py-ta-go cho \(\Delta ADC\) ta có :
\(AC=\sqrt{AD^2+CD^2}=\sqrt{8^2+15^2}=17cm\)
b ) Ta có : \(\Delta MDA\sim\Delta DCA\) ( tự chứng minh )
\(\Rightarrow\) \(\dfrac{MD}{CD}=\dfrac{AD}{AC}\)
\(\Rightarrow\) \(MD=\dfrac{CD.AD}{AC}=\dfrac{15.8}{17}=7,1cm\)