Cho hình chữ nhật ABCD có AB = a, AC = \(a\sqrt{5}\). Tính:
a. \(\left|3\overrightarrow{AB}-4\overrightarrow{BC}\right|\)
b. \(\left|2\overrightarrow{BA}+3\overrightarrow{BC}\right|\)
c. \(\left|\overrightarrow{AD}+3\overrightarrow{BC}\right|\)
d. \(\left|2\overrightarrow{DC}-3\overrightarrow{AB}\right|\)
\(BC=AD=\sqrt{AC^2-AB^2}=2a\)
a/ \(T=\left|3\overrightarrow{AB}-4\overrightarrow{BC}\right|\Rightarrow T^2=9AB^2+16BC^2-24\overrightarrow{AB}.\overrightarrow{BC}\)
\(=9a^2+64a^2=73a^2\Rightarrow T=a\sqrt{73}\)
b/ \(T^2=4AB^2+9BC^2+12.\overrightarrow{BA}.\overrightarrow{BC}=4AB^2+9BC^2=40a^2\)
\(\Rightarrow T=2a\sqrt{10}\)
c/ \(T=\left|\overrightarrow{AD}+3\overrightarrow{BC}\right|=\left|\overrightarrow{AD}+3\overrightarrow{AD}\right|=\left|4\overrightarrow{AD}\right|=4AD=8a\)
d/ \(T=\left|2\overrightarrow{DC}-3\overrightarrow{DC}\right|=\left|-\overrightarrow{DC}\right|=CD=AB=a\)
