\(y=f\left(x\right)=2x+1\)
\(f\left(0\right)=2\cdot0+1=0+1=1\\ f\left(1\right)=2\cdot1+1=2+1=3\\ f\left(-2\right)=2\cdot\left(-2\right)+1=-4+1=-3\)
cái này ta chỉ cần thay x là đc
f ( 0 ) = \(2.0+1=0+1=1\)
\(f\left(1\right)=2.1+1=2+1=3\)
\(f\left(-2\right)=2.\left(-2\right)+1=\left(-4\right)+1=\left(-3\right)\)