+ \(f\left(a+b\right)=f\left(a\cdot b\right)\) (1)
+ Thay \(a=0,b=-\dfrac{1}{2}\) vào (1) ta có :
\(f\left(0-\dfrac{1}{2}\right)=f\left(0\cdot-\dfrac{1}{2}\right)\)
\(\Rightarrow f\left(-\dfrac{1}{2}\right)=f\left(0\right)\)
\(\Rightarrow f\left(0\right)=-\dfrac{1}{2}\)
+ Thay \(a=0,b=2016\) vào (1) ta có :
\(f\left(0+2016\right)=f\left(0\cdot2016\right)\)
\(\Rightarrow f\left(2016\right)=f\left(0\right)\)
\(\Rightarrow f\left(2016\right)=-\dfrac{1}{2}\)