Lời giải:
Với mọi $x\in\mathbb{R}$:
\(f(x)=a(2024^x-2024^{-x})+bx^{2023}+2025\)
\(\Rightarrow f(-x)=a(2024^{-x}-2024^{-(-x)})+b(-x)^{2023}+2025=a(2024^{-x}-2024^x)-bx^{2023}+2025\)
$\Rightarrow f(x)+f(-x)=4050$
Thay \(x=1-\sqrt[4]{8}=1-2^{\frac{3}{4}}\) thì:
\(f(2^{\frac{3}{4}}-1)=4050-f(1-2^{\frac{3}{4}})=4050-10=4040\)