Question

Cho \(\dfrac{x+16}{9}=\dfrac{y-25}{16}=\dfrac{z+9}{25}\) và \(2x^3-1=15\). Tính B = \(x+y+z\)

Answer 1

\(2x^3-1=15\)

\(\Rightarrow2x^3=16\)

\(\Rightarrow x^3=8\)

\(\Rightarrow x=2\)

Thay x vào \(\dfrac{x+16}{9}=\dfrac{y-25}{16}+\dfrac{z+9}{25}\) thì tìm được y và z

Tính nốt x + y + z

Answer 2

\(2x^3-1=15\)

\(2x^3=16\)

\(x^3=8\)

\(\Rightarrow x=2\)

\(\dfrac{x+16}{9}=\dfrac{y+25}{16}=\dfrac{z+9}{25}\)

\(\Leftrightarrow\dfrac{2+16}{9}=\dfrac{y-25}{16}=\dfrac{z+9}{25}\)

\(\Leftrightarrow\dfrac{y-25}{16}=\dfrac{z+9}{25}=\dfrac{18}{9}=2\)

\(\Rightarrow\dfrac{y-25}{16}=2\)

\(\Rightarrow y-25=32\)

\(\Rightarrow y=57\)

\(\Rightarrow\dfrac{z+9}{25}=2\)

\(\Rightarrow z+9=50\)

\(\Rightarrow z=41\)

\(\Rightarrow\)\(x=2\) , \(y=57\) , \(z=41.\)

\(B=x+y+z\)

\(B=2+57+41\)

\(B=100\)

Vậy \(B=100\)