a:
\(AD=\dfrac{1}{3}\cdot6=2\left(cm\right)\)
Xét ΔABC có DE//BC
nên AD/AE=AB/AC
=>AD/AB=AE/AC
hay AD/6=AE/9
=>AE/9=2/6=1/3
=>AE=3cm
b: \(S_{AED}=\dfrac{2\cdot3}{2}=3\left(cm^2\right)\)
\(S_{ABC}=\dfrac{6\cdot9}{2}=27\left(cm^2\right)\)
=>\(S_{BDEC}=27-3=24\left(cm^2\right)\)