\(\Rightarrow D=\dfrac{2}{x^2+y^2}+\dfrac{2}{2xy}+\dfrac{2}{xy}\ge2\cdot\dfrac{4}{x^2+2xy+y^2}+\dfrac{2}{\dfrac{\left(x+y\right)^2}{4}}=\dfrac{4}{\left(x+y\right)^2}+\dfrac{8}{\left(x+y\right)^2}=\dfrac{4}{4}+\dfrac{8}{4}=3\) Dấu = xảy ra \(\Leftrightarrow x=y=1\)