Question

Cho dãy số (u_n) : \(\left\{{}\begin{matrix}u_1=-1\\u_{n+1}=\dfrac{2}{u_n}+\dfrac{u_n}{2},n\ge1\end{matrix}\right.\) và dãy v_n = \(\dfrac{u_n-2}{u_n+2}\)

Tìm u₂₀₁₅ và v₂₀₁₅

Answer 1

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