Có: \(\sqrt{x+4\sqrt{x-4}}\)=\(\sqrt{x-4+2\sqrt{x-4}+4}\)=\(\sqrt{\left(\sqrt{x-4}+2\right)^2}\)=\(\sqrt{x-4}\)+2
\(\sqrt{x-4\sqrt{x-4}}\)=\(\sqrt{x-4-4\sqrt{x-4}+4}\)=\(\sqrt{\left(\sqrt{x-4}-2\right)^2}\)=2-\(\sqrt{x-4}\) vì x<8
suy ra x-4<4 \(\Rightarrow\)\(\sqrt{x-4}\)<2\(\Rightarrow\)\(\sqrt{x-4}\)-2<0
Khi đó biểu thức Q trở thành
Q=\(\sqrt{x-4}\)+2+2-\(\sqrt{x-4}\)=4
vậy Q=4