Question

 \(P=\dfrac{x\sqrt{x}-8}{x+2\sqrt{x}+4}+3\left(1-\sqrt{x}\right)\)

Answer 1

ĐKXĐ : \(x\ge0\)

\(P=\dfrac{x\sqrt{x}-8}{x+2\sqrt{x}+4}+3\left(1-\sqrt{x}\right)\)

\(=\dfrac{\left(\sqrt{x}-2\right)\left(x+2\sqrt{x}+4\right)}{x+2\sqrt{x}+4}+3-3\sqrt{x}\)

\(=\sqrt{x}-2+3-3\sqrt{x}\)

\(=-2\sqrt{x}+1\)

Answer 2

   \(P=\dfrac{x\sqrt{x}-8}{x+2\sqrt{x}+4}+3\left(1-\sqrt{x}\right)\)

       \(=\dfrac{\sqrt{x^3}-2^3}{x+2\sqrt{x}+4}+3\left(1-\sqrt{x}\right)\)

       \(=\dfrac{\left(\sqrt{x}-2\right)\left(x+2\sqrt{x}+4\right)}{x+2\sqrt{x}+4}+3\left(1-\sqrt{x}\right)\)

       \(=\sqrt{x}-2+3-3\sqrt{x}\)

       \(=1-2\sqrt{x}\)