Sửa đề: \(P=\dfrac{2}{2x+3}+\dfrac{3}{2x+1}-\dfrac{6x+5}{\left(2x+3\right)\left(2x+1\right)}\)
a: ĐKXĐ: \(x\notin\left\{-\dfrac{3}{2};-\dfrac{1}{2}\right\}\)
b: \(A=\dfrac{4x+2+6x+9-6x-5}{\left(2x+3\right)\left(2x+1\right)}=\dfrac{4x+6}{\left(2x+3\right)\left(2x+1\right)}=\dfrac{2}{2x+1}\)
c: Để P=-1 thì 2x+1=-2
=>2x=-3
hay x=-3/2(loại)