\(A=1+3+3^2+3^3+...+3^{3n}+3^{3n+1}+3^{3n+2}\)
\(A=1.\left(1+3+9+\right)+3^3.\left(1+3+9\right)+3^6.\left(1+3+9\right)+...+3^{3n}.\left(1+3+9\right)\)
\(A=1.13+3^3.13+3^6.13+....+3^n.13\)
\(A=13.\left(1+3^3+3^6+...+3^{3n}\right)\)⋮ \(13\)
Vậy \(A\) ⋮ \(13\) ∀ \(n\)