\(\Leftrightarrow m\left(x^2-2x\right)+x^2-4x+4>0\)
\(\Leftrightarrow mx\left(x-2\right)+\left(x-2\right)^2>0\)
\(\Leftrightarrow\left(x-2\right)\left(mx+x-2\right)>0\)
\(\Leftrightarrow mx+x-2< 0\) (do \(x-2< 0\) \(\forall x\in\left[0;1\right]\))
\(\Leftrightarrow mx< 2-x\)
- Với \(x=0\) luôn thỏa mãn
- Với \(x>0\Rightarrow m< \frac{2-x}{x}=\frac{2}{x}-1\Rightarrow m< \min\limits_{\left[0;1\right]}\left(\frac{2}{x}-1\right)=1\)
Vậy \(m< 1\)