Gọi tọa độ trọng tâm tam giác ABC là G(\(x_G;y_G\))
\(\Rightarrow\left\{{}\begin{matrix}x_G=\frac{x_A+x_B+x_C}{3}\\y_G=\frac{y_A+y_B+y_C}{3}\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x_G=\frac{1+3+6}{3}\\y_G=\frac{1+2+5}{3}\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x_G=\frac{10}{3}\\y_G=\frac{8}{3}\end{matrix}\right.\)\(\Rightarrow G\left(\frac{10}{3};\frac{8}{3}\right)\)
Vậy tọa độ trọng tâm tam giác ABC là \(G\left(\frac{10}{3};\frac{8}{3}\right)\)