a: \(A=\dfrac{x\left(x-1\right)^2\cdot\left(x+1\right)^2}{x^2+1}:\left[\left(x+1\right)^2\cdot\left(x-1\right)^2\right]\)
\(=\dfrac{x}{x^2+1}\)
b: Khi x=-1/2 thì \(A=\dfrac{-1}{2}:\left(\dfrac{1}{4}+1\right)=\dfrac{-1}{2}:\dfrac{5}{4}=\dfrac{-2}{5}\)
c: Để A=1/2 thì \(\dfrac{x}{x^2+1}=\dfrac{1}{2}\)
\(\Leftrightarrow x=1\)(loại)