a ) Xét \(\Delta ADB\) và \(\Delta EDB\) có :
\(\widehat{BAD}=\widehat{DEB}=90^o;\widehat{ABD}=\widehat{EBD};BD:chung\)
\(\Rightarrow\) \(\Delta ADB\) = \(\Delta EDB\) ( ch - gn )
\(\Rightarrow\) AD = DE
b) Xét \(\Delta ADE\) và \(\Delta EDC\) có:
\(\widehat{FAD}=\widehat{CED}=90^o;AD=DE;\widehat{ADF}=\widehat{EDC}\)
\(\Rightarrow\) \(\Delta ADF\) = \(\Delta EDC\)
\(\Rightarrow\) DF = DC